In the continuation of our series of studies to determine the dosage of oxidant or chemical required to oxidize or scavenge sulfide, Dr. Greg Simpson, PhD, experimentally evaluates hydrogen peroxide (H2O2) versus chlorine dioxide (ClO2).
The Results of Hydrogen Peroxide versus Chlorine Dioxide
In the evaluation of the parts-per-million (ppm) of chemical required to oxidize one ppm of sulfide, the resulting experiment demonstrated an approximate required amount of 8.4 ppm of H2O2 at an unbuffered pH needed per ppm of sulfide to completely scavenge sulfide, when compared to a range of 2.9 to 3.4 ppm ClO2 at an unbuffered pH for successful oxidation of a ppm of sulfide. At a buffered pH-5, the data demonstrated an approximate 3.7 ppm ClO2 is needed to oxidize one ppm of sulfide.
Hydrogen Peroxide vs Chlorine Dioxide Experiment
What is of particular interest in this experiment was the reaction time required for H2O2. The data through this experiment showed at a pH of 5, without the presence of a catalyst such as iron, the reaction time of hydrogen peroxide was extraordinarily slow. This is in contrast to common use of H2O2 in produced water. A possible reason for H2O2’s typical effectiveness is that produced water does contain some iron, which serves as a catalyst for typically seen reaction times.
To view the experiment setup, and resulting data, you can read Dr. Greg Simpson’s writeup comparing H2O2 to ClO2 below!
If you have questions about the testing done within the paper or are curious to know how PureLine can provide a superior solution for your systems, please contact us below!